The present ages of three persons are in the ratio of 4: 7:9 Eight years ago, the sum of their ages was 56. what are their present ages in years?

The present ages of three persons are in the ratio of 4: 7:9 Eight years ago, the sum of their ages was 56. what are their present ages in years? Correct Answer 16, 28, 36

Let, their present ages be, 4x, 7x, 9x respectively Then, ( 4x - 8) + ( 7x - 8) + ( 9x - 8) = 56 20x = 80 x = 4 Present ages are 4x = 16, 7x = 28 and 9x = 36 years
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