A's age six years ago was equal to twice of B's age four years ago. C is nine years elder to B and also nine years younger to A. What is the sum of present ages of A, B and C?
A's age six years ago was equal to twice of B's age four years ago. C is nine years elder to B and also nine years younger to A. What is the sum of present ages of A, B and C? Correct Answer 87 years
Calculation:
Let be assume present age of A, B, and C is A, B, and C
⇒ (A - 6) = 2 × (B - 4) ...1)
⇒ C = B + 9 ...2)
⇒ C = A - 9 ...3)
⇒ By solving equation (1), (2) and (3)
⇒ A = 38, B = 20, C = 29
⇒ The sum of present age of A, B, and C = A + B + C = 38 + 20 + 29 = 87
∴ The required result will be 87.
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Feb 20, 2025