In a family of 4 persons, age of Father 4 years ago was equal to thrice the present age of son. Ratio of present age of wife to that of daughter is 7 : 3. Ratio of age of daughter after 3 years to the present age of Son is 3 : 2. What is the difference between present ages of father & twice the present age of daughter?

In a family of 4 persons, age of Father 4 years ago was equal to thrice the present age of son. Ratio of present age of wife to that of daughter is 7 : 3. Ratio of age of daughter after 3 years to the present age of Son is 3 : 2. What is the difference between present ages of father & twice the present age of daughter? Correct Answer 10 years

Let present age of father, wife, daughter & son be f, w, d, s years respectively

⇒ f – 4 = 3s

⇒ w : d = 7 : 3

⇒ (d + 3) : s = 3 : 2

Suppose s = k

⇒ f = 3k + 4

⇒ d = (3k – 6)/2

Required difference = f – 2d

= 3k + 4 – (3k – 6) = 10 years

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Consider the 5 × 5 matrix \[{\text{A}} = \left[ {\begin{array}{*{20}{c}} 1&2&3&4&5 \\ 5&1&2&3&4 \\ 4&5&1&2&3 \\ 3&4&5&1&2 \\ 2&3&4&5&1 \end{array}} \right