ksec2θ+cosec2θ=2 ⇒k21cos2θ+1sin2θ=4
⇒k2sin2cos2θsin2θ+cos2θ=4
⇒4k2sin2θ cos2θ = 16 ⇒ksin2θ2=42 ... ... ... (i)
-kcos2θcos2θ+sin2θ=3⇒(kcos2θ)2=32... ... ... (ii)
(i) + (ii) করে পাই, k2(sin22θ+cos22θ)=25 ⇒k =±5
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