I want to create a 12' diameter cylinder grain tower that's 55' high, and has a smooth surface and dome roof. How many yards of concrete does it take to anchor it for an estimated maximum wind force of 110 MPH?

The force will be around 0.0012 x ((88/60) x (110))^2. The 88/60 converts from mph to fps, and the answer is around 31 pounds per square feet. If we add the height of the dome, it is 55 + 6 = 61' tall, and 12' wide, so the area is 12 x 61 = 732 square feet. Total force acting on the tower is about 732 x 31 = 22,692 pounds, over ten tons. The force will be greatest near the top, because wind is strongest higher up, and the top will be more turbulent. Without knowing the wind gradient one can't be sure where the net force acts. You'll have to pour enough concrete to withstand over ten tons sideways near the top of your tower. We're out of space here - good luck!