If 4.5 gm Aluminium completely reacts with 4gm of oxygen. Then what will be empirical formula of aluminium oxide.
If 4.5 gm Aluminium completely reacts with 4gm of oxygen. Then what will be empirical formula of aluminium oxide.
A. `Al_(2)O`
B. `Al_(2)O_(3)`
C. `AlO_(2)`
D. `AIO`
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`Al+O_(2)rarrAl_(x)O_(y)`
`n_(Al)=(4.5)/(27)=(1)/(6) n_(o_(2))=(4)/(52)=(1)/(8) (n_(Al))/(n_(o))=(1)/(6)xx(4)/(1)=(2)/(3)`
`n_(o)=2xxn_(o_(2))=(1)/(4) "Formula"=Al_(2)O_(3)`
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