Empirical formula of a compound is `CH_(2)O`. If its vapour density is 90, then the molecular formula of the compound is
Empirical formula of a compound is `CH_(2)O`. If its vapour density is 90, then the molecular formula of the compound is
A. `C_(5)H_(10)O_(5)`
B. `C_(3)H_(6)O_(3)`
C. `C_(6)H_(12)O_(6)`
D. `C_(4)H_(8)O_(4)`
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Correct Answer - C
M.Mass `=2xxV.D=2xx90=180`
For other details see solution of question 42
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