Empirical formula of a compound is `CH_(2)O` and its molecular mass is 90. The molecular formula of the compound is
Empirical formula of a compound is `CH_(2)O` and its molecular mass is 90. The molecular formula of the compound is
A. `C_(2)H_(4)O_(2)`
B. `C_(3)H_(6)O_(3)`
C. `C_(4)H_(8)O_(4)`
D. `CH_(2)O`
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Correct Answer - C
E.F. mass `= 12+2xx1+16=30`
Mol. Mass = 120
`n = ("Mol. Mass")/("E.F. mass")=(120)/(3)=4`
`:.` Mol formula `= (CH_(2)O)_(4) = C_(4)H_(8)O_(4)`
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