How many moles of `BaCl_(2)` would be needed to make 250 ml of a solution having the same concentration of `Cl^(-)` as one containing 1.17 g NaCl per

Question

How many moles of `BaCl_(2)` would be needed to make 250 ml of a solution having the same concentration of `Cl^(-)` as one containing 1.17 g NaCl per

How many moles of `BaCl_(2)` would be needed to make 250 ml of a solution having the same concentration of `Cl^(-)` as one containing 1.17 g NaCl per 100ml?
A. 0.1
B. 0.01
C. 0.05
D. 0.025

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
`[Cl^(-)]_(NaCl)=(1.17)/(58.5)xx(1000)/(100)=[Cl^(-)]_(BaCl_(2))`
`therefore [Cl^(-)]_(BaCl_(2))=("mole "Cl^(-))/((250)/(1000))=0.2`
Mole of `Cl^(-)=0.2 xx(1)/(4)`
`therefore` mole of `BaCl_(2) = 0.2 xx(1)/(4)xx(1)/(2)=0.025`

4 views Answered 2023-02-05 15:29