What mass of `(NH_(4))_2CO_(3)` with contains `6.022 xx 10^(23)` hydrogen atoms?
What mass of `(NH_(4))_2CO_(3)` with contains `6.022 xx 10^(23)` hydrogen atoms?
A. 1.92 g
B. 12 g
C. 19.2 g
D. 25.4 g
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Correct Answer - B
`(NH_(4))_(2)CO_(3)`
`because` 8 mole H-atom present in 1 mole `(NH_(4))_(2)CO_(3)`
`therefore 6.022 xx 10^(23)` H-atom present in `(1)/(8) xx 1` mole `(NH_(4))_(2)CO_(3)`
or 1 mole H-atom
`therefore` Mass of `(1)/(8)` mole `(NH_(4))_(2)CO_(3) = (1)/(8)[36+12+48]=96//8=12g`
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