At `-50^(@)C` liquid `NH_(3)` has ionic product is `10^(-30)` .How many amide `(NH_(2)^(-))` ions are present per mm`.^(3)` in pure liqudi `NH_(3)`? (

Question

At `-50^(@)C` liquid `NH_(3)` has ionic product is `10^(-30)` .How many amide `(NH_(2)^(-))` ions are present per mm`.^(3)` in pure liqudi `NH_(3)`? (

At `-50^(@)C` liquid `NH_(3)` has ionic product is `10^(-30)` .How many amide `(NH_(2)^(-))` ions are present per mm`.^(3)` in pure liqudi `NH_(3)`? (Take `N_(A)=6xx10^(23)`)

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

`K=[NH_(4)""^(+)][NH_(2)""^(=)]=10^(-30)`
`[NH_(2)^(-)]=[NH_(4)^(+)]=10^(-15)M " "( :.2NH_(3)hArr NH_(4)^(+)+NH_(2)""^(-))`
No. of `NH_(2)^(-)` ions `NH_(2)^(-)=((10^(-15)mol e)/(L))((1L)/(10^(6)mm^(3)))((6xx10^(23)ions)/(mol e))=600ions//mm^(3)`

4 views Answered 2023-02-05 15:29