Sulphur trioxide is preapared by the following two reactions: `S_(8)(s)+8O_(2)(g)to 8SO_(2)(g)` `2SO_(2)(g)+O_(2)(g) to 2SO_(3)(g)` How many grams of
Sulphur trioxide is preapared by the following two reactions:
`S_(8)(s)+8O_(2)(g)to 8SO_(2)(g)`
`2SO_(2)(g)+O_(2)(g) to 2SO_(3)(g)`
How many grams of `SO_(3)` are produced from 1 mole fo `S_(8)`?
A. 1280
B. 640
C. 960
D. 320
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Correct Answer - B
Form the given reaction, it is clear that 1 mole of `S_(8)` will given 8 moles of `SO_(3)`.
Mass of `SO_(3)` formed = Number of moles `xx` Molar mass `= 8 xx 80 = 640g`]
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