When x grams of steam at `100^(@)C` is mixed with y grams of ice at `0^(@)C`, we obtain `(x + y)` grams of water at `100^(@)C`. What is the ratio `y//

Question

When x grams of steam at `100^(@)C` is mixed with y grams of ice at `0^(@)C`, we obtain `(x + y)` grams of water at `100^(@)C`. What is the ratio `y//

When x grams of steam at `100^(@)C` is mixed with y grams of ice at `0^(@)C`, we obtain `(x + y)` grams of water at `100^(@)C`. What is the ratio `y//x` ?
A. 1
B. 2
C. 3
D. 4

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - C
Heat given out when x grams of steam at `100^(@)C` is converted to water at `100^(@)C`
`H_(1) = 540 x` .......(1)
Heat gained by ice at `0^(@)C` to convert to water at `100^(@)C`
`H_(2) = 80y + y xx 1 xx (100 - 0)`
`H_(2) = 180y` ....(2)
According to principle of calorimetry,
`H_(1) = H_(2)`
`540 x = 180 y`
`(y)/(x) = 3`