What is the free energy charge `(DeltaG)` when 1.0 mole of water at `100^(@)C` and 1 atm pressure is converted into steam at ` 100^(@)C` and 1 atm pre

Question

What is the free energy charge `(DeltaG)` when 1.0 mole of water at `100^(@)C` and 1 atm pressure is converted into steam at ` 100^(@)C` and 1 atm pre

What is the free energy charge `(DeltaG)` when 1.0 mole of water at `100^(@)C` and 1 atm pressure is converted
into steam at ` 100^(@)C` and 1 atm pressure ?
A. 80 cal
B. 540 cal
C. 620 cal
D. zero

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
`DeltaG^(@)` = 0 at equilibrium

4 views Answered 2023-02-05 15:29