`DeltaG = DeltaH - TDeltaS` and `DeltaG + T[(d(DeltaG))/(dT)]_(p)` then `((dE_(cell)/(dT))` is:

Question

`DeltaG = DeltaH - TDeltaS` and `DeltaG + T[(d(DeltaG))/(dT)]_(p)` then `((dE_(cell)/(dT))` is:

`DeltaG = DeltaH - TDeltaS` and `DeltaG + T[(d(DeltaG))/(dT)]_(p)` then `((dE_(cell)/(dT))` is:
A. `(trangleS)/(nF)`
B. `(nE)/(triangleS)`
C. `-nFE^(cell)`
D. `+nEF_(cell)`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
`triangleS-{(d)/(dT)(triangleG)}_(P)=+nF((dE)/(dT))_(p)`
`((dE)/(dT))_(p)=(triangleS)/(nF)`

4 views Answered 2023-02-05 15:29