At `0^(@)C` ice and water are in equilibrium and `DeltaH=6kJ" "mol^(-1)` for this process: `H_(2)OhArrH_(2)O(l)` The values of `DeltaS and DeltaG` for
At `0^(@)C` ice and water are in equilibrium and `DeltaH=6kJ" "mol^(-1)` for this process:
`H_(2)OhArrH_(2)O(l)`
The values of `DeltaS and DeltaG` for conversion of ice into liquid water at `0^(@)C` are:
A. `-21.9JK^(-1)mol^(-1)` and 0
B. `0.219JK^(-1) mol^(-1) and 0`
C. `21.9JK^(-1)mol^(-1) and 0`
D. `0.0219JK^(-1)mol^(-1) and 0`
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Correct Answer - C
`DeltaG=0`
`thereforeH-TDeltaS=0`
`DeltaS=(DeltaH)/(T)=(6000)/(273)=21.9JK^(-1)mol^(-1)`
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