How many kilogram of pure `H_(2)SO_(4)` could be obtained from 1kg of iron `(FeSS_(2))` according to the following reactions?
`4FeS_(2)+11O_(2) to2Fe_(2)O_(3)+8SO_(2)`
`2SO_(2)+O_(2)to2SO_(3)`
`SO_(3)+H_(2) to H_(2)SO_(4)`

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Final balanced eqution,
`underset(4xx120g)underset("4mol")(3FeS_(2))+15O_(2)+8H_(2)O to 2Fe_(2)O_(3)+underset(8xx98g)underset("8mol")(3FeS_(2))8H_(2)SO_(4)`
`4xx120"g of" FeS_(2)"yield" H_(2)SO_(4) to 2Fe_(2)O_(3)=8xx98g`
`"1000g of "FeS_(2)"will yeild"H_(2)SO_(4)=(8xx98)/(4xx120)xx1000` =1.63kg

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