If `Delta H_(f)^(@)` for `Ag^(+)` (infinitely diluted), `NO_(3)^(-)` (infinitely diluted), `Cl^(-)` (infinitely diluted) and `AgCl(s)` are `10.5 .579-

Question

If `Delta H_(f)^(@)` for `Ag^(+)` (infinitely diluted), `NO_(3)^(-)` (infinitely diluted), `Cl^(-)` (infinitely diluted) and `AgCl(s)` are `10.5 .579-

If `Delta H_(f)^(@)` for `Ag^(+)` (infinitely diluted), `NO_(3)^(-)` (infinitely diluted), `Cl^(-)` (infinitely diluted) and `AgCl(s)` are `10.5 .579-207.36, -67.159` and `-127.068` respectively. Calculate the enthalpy change for the reaction
`AgNO_(3)(aq.)rarr+HCl(aq.)rarrAgCl(s)+HNO_(3)(aq.)`
A. `21.471 KJ//mol`
B. `145.688 KJ//mol`
C. `-65 488KJ//mol`
D. None

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`DeltaH_("reaction")^(@)=[DeltaH_(f)(AgCl)+DeltaH_(f)(H^(+))+DeltaH_(f)(NO_(3)^(-))]`
`-[DeltaH_(f)^(@)(Ag^(+))+DeltaH_(f)^(@)(NO_(3)^(-))]`
`-[DeltaH_(f)^(@)(Ag^(+))+DeltaH_(f)^(@)(NO_(3)^(-))]+DeltaH_(f)^(@)(Cl^(-))+DeltaH_(f)^(@)(H^(+))]`
`=-127.068-[105.579-167.159]= -65.488KJ//mol`.

5 views Answered 2023-02-05 15:29