For a reaction `DeltaH=+29kJ" "mol^(-1),DeltaS=-35KJ^(-1)" "mol^(-1)` at what temperature, the reaction will be spontaneous?

Question

For a reaction `DeltaH=+29kJ" "mol^(-1),DeltaS=-35KJ^(-1)" "mol^(-1)` at what temperature, the reaction will be spontaneous?

For a reaction
`DeltaH=+29kJ" "mol^(-1),DeltaS=-35KJ^(-1)" "mol^(-1)`
at what temperature, the reaction will be spontaneous?
A. `828.7^(@)C`
B. `828.7K`
C. Spontaneous at all temperature
D. non possible

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
`DeltaG=DeltaH-TDeltaS`
When `DeltaH=+ve,DeltaS=-ve` then `DeltaG` will be positive and the reaction is non-spontaneous.

4 views Answered 2023-02-05 15:29