The free energy for a reaction having `DeltaH=31400` cal, `DeltaS=32" cal "K^(-1)mol^(-1)` at `1000^(@)C` is:

Question

The free energy for a reaction having `DeltaH=31400` cal, `DeltaS=32" cal "K^(-1)mol^(-1)` at `1000^(@)C` is:

The free energy for a reaction having `DeltaH=31400` cal, `DeltaS=32" cal "K^(-1)mol^(-1)` at `1000^(@)C` is:
A. `-9336cal`
B. `-7386cal`
C. `-1936cal`
D. `+9336cal`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Related Questions

For the f reaction at `300K` `A(g)+B(g) to C(g)` `DeltaU = - 3.0 k cal" "," "DeltaS = - 10.0 cal //K` Value of the `DeltaG` is

2 Answers 5 Views

For a given reaction, `DeltaH=35.5 KJ "mol"^(-1)` and `DeltaS=83.6 JK^(-1) "mol"^(-1)`. The reaction is spontaneous at: (Assume that `DeltaH and delta

2 Answers 5 Views

For the reaction `F_(2)(g)+2HCL(g)rarr2HF(g)+C1_(2)(g)` `DeltaH^(@)` at `298K` is `-84.4Kcal` , `DeltaH^(@)f(HF)=-64.2Kcal//mol` `DeltaH^(@)f` for the

2 Answers 5 Views

Melting point of a solid is x K and its latent heat of fusion is 600 cal `mol^(-1)`. The entropy change for fusion of 1 mol solid is 2 cal `mol^(-1)K^

2 Answers 4 Views

For a reaction, `Ag_(2)O(s)hArr2Ag(s)+(1)/(2)O_(2)(g)` `DeltaH,DeltaS and T ` are 40.63 kJ `mol^(-1)`, 108.8 J `K^(-1)mol^(-1) and 373.3K` respectivel

2 Answers 5 Views

For the homogeneous reactions: `xA+yBtolY+mZ` `DeltaH=-30kJ" "mol^(-1),DeltaS=-100JK^(-1)" "mol^(-1)` At what temperature the reaction is at equilibri

2 Answers 6 Views

For a reaction `DeltaH=+29kJ" "mol^(-1),DeltaS=-35KJ^(-1)" "mol^(-1)` at what temperature, the reaction will be spontaneous?

2 Answers 4 Views

For the reaction, `4C(s) +5H_(2)(g) rarr nC_(4)H_(10)(g)`, `DeltaH^(Theta) =- 124.73 kJ mol^(-1), DeltaS^(Theta) =- 365.8 J K^(-1) mol^(-1)` `4C(s) +5

2 Answers 4 Views

Consider the values of `DeltaH("in" kJ mol^(-))` and for `DeltaS("in" mol^(-)K^(-1))` given for four different reactions. For which reaction will `Del

2 Answers 5 Views

For the reaction `2Ag_(2)O(s) rarr 4Ag(s) + O_(2)(g), DeltaH ` is 61.17 `KJ"mol"^(-1)` and `DeltaS` is 132 `JK^(-1) "mol"^(-1)` . Compute the temperat

2 Answers 5 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
`DeltaG=DeltaH-TDeltaS=31400-1273xx32=-9336kcal`

4 views Answered 2023-02-05 15:29