Calculate equilibrium constant for `I_(2)+I^(-) hArr I_(3)^(-)` at 298 K from the following information : `{:(I_(2) (aq.)+2e^(-) rarr 2I^(-),,E^(@)=0.
Calculate equilibrium constant for
`I_(2)+I^(-) hArr I_(3)^(-)`
at 298 K from the following information :
`{:(I_(2) (aq.)+2e^(-) rarr 2I^(-),,E^(@)=0.6197" volt"),(I_(3)^(-)+2e^(-) rarr 3I^(-),,E^(@)=0.5355" volt"):}`
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Correct Answer - 706.9
`{:(I_(2)+2e^(-) rarr 2I^(-)," "E^(@)=0.6197" volt"),(3I^(-) rarr I_(3)^(-)+2e^(-)," "E^(@)=-0.5355" volt"),(bar(I_(2)+I^(-) hArr I_(3)^(-),)" "E^(@)=0.6197-0.5355),(" "=0.0842" volt"):}`
`K="antilog" [(nE^(@))/0.0591]="antilog"[(2xx0.0842)/0.0591]=706.9`
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