Calculate equilibrium constant for the reaction : `Zn+Cd^(2+) hArr Zn^(2+)+Cd`, (Given `E_(cell)^(@)=0.36 "V "`)

Calculate equilibrium constant for the reaction :
`Zn+Cd^(2+) hArr Zn^(2+)+Cd`,
(Given `E_(cell)^(@)=0.36 "V "`)

Monjur Alahi

7 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

Correct Answer - `1.52xx10^(12)`
`E_(cell)^(@)=(0.0591)/(n)logK_(C)`
`logK_(C)=(E_(cell)^(@)xxn)/(0.0591)=((0.36)xx2)/(0.0591)=12.1827,K_(C)="Antilog "12.1827=1.52xx10^(12)`

7 views Answered 2023-02-05 15:29

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