A cell reaction is given as :
`A (s)+B^(2+)(aq)harrA^(2)(aq)+B(s)`
Equilibrium constant `(K_(c))` for the cell is 10. Calculate `E_(cell)^(@)`.

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`K_(c)`=10, n=2
`log K_(c)=(nE_(cell)^(@))/(0.0591) " or " E_(cell)^(@)=(0.0591xx"log" K_(c))/(2)`
`E_(cell)^(@)=(0.0591xxlog10)/(2)=0.02955 V`.

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