Calculate equilibrium constant for the reaction at `25^(@)C` `Cu(s)+2Ag^(+)(aq) hArr Cu^(2+)(aq)+2Ag(s)` `E^(@)` value of the cell is 0.46`" V "`.

Calculate equilibrium constant for the reaction at `25^(@)C`
`Cu(s)+2Ag^(+)(aq) hArr Cu^(2+)(aq)+2Ag(s)`
`E^(@)` value of the cell is 0.46`" V "`.

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

`E_(cell)`=0.46 V, n=2
`log K_(c)=(nE_(cell)^(@))/(0.0591)=(2xx0.46)/(0.0591)=15.6`
`K_(c)="Antilog " 15.6=3.98xx10^(15)`.

4 views Answered 2023-02-05 15:29

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