Determine the equilibrium constant of the following reaction at 298 K : `2Fe^(3+)+Sn^(2+) rarr 2Fe^(2+) +Sn^(4+)` `("Given: "E_(Sn^(4+)//Sn^(2+))^(@)=

Question

Determine the equilibrium constant of the following reaction at 298 K : `2Fe^(3+)+Sn^(2+) rarr 2Fe^(2+) +Sn^(4+)` `("Given: "E_(Sn^(4+)//Sn^(2+))^(@)=

Determine the equilibrium constant of the following reaction at 298 K :
`2Fe^(3+)+Sn^(2+) rarr 2Fe^(2+) +Sn^(4+)`
`("Given: "E_(Sn^(4+)//Sn^(2+))^(@)=0.15" volt, "E_(Fe^(3+)//Fe^(2+))^(@)=0.771" volt"` )

Monjur Alahi

8 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - `K=1.0xx10^(21)`
Calculate `E_(cell)^(@)`. The value is 0.21 volt.
Apply `E_(cell)^(@)=0.0591/2 log K`

8 views Answered 2023-02-05 15:29