A far sighted person has a near point of `60"cm"` . What power lens should be used for eye glasses such that the person can be read this book at a distance of `25` cm.

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Here `v=-60"cm" , u=-25"cm"`
`(1)/(f) = (1)/(v) - (1)/(u) = -(1)/(60) + (1)/(25) implies f= (300)/(7) "cm" therefore "Power" = (1)/("f(inm") = (1)/((3//7)) = +2.33D`

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