The nearer point of hypermetropic eye is 40 cm. The lens to used for its correction should have the power
The nearer point of hypermetropic eye is 40 cm. The lens to used for its correction should have the power
A. `+1.5D`
B. `-1.5D`
C. `+2.5D`
D. `+0.5D`
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Correct Answer - C
(c ) Hypermetropia can be removed by using a convex lens.
Focal length of used lens, f=+d=+40 cm
=+(defected near point)
`therefore` Power of lens=`100/(f(cm))=100/40=2.5D.`
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