The ratio of the weight of a man in a stationary lift and when it is moving downward with uniform acceleration ‘ a ’ is `3 : 2`. The value of ‘ a ’ is ( g - Acceleration due to gravity of the earth)
A. `(g)/(3)`
B. `(g)/(2)`
C. `g`
D. `(4)/(3)g`

6 views

1 Answers

Correct Answer - A
`(mg)/(m(g-a))=(3)/(2)`
`2g=3(g-a)`
`a=(g)/(3)`

6 views

Related Questions