You step into an elevator, and it accelerates to a downward speed of 9.2 m/s in 2.1 s. How does your apparent weight during this acceleration compare with your actual weight? Apparent weight is
A. 55% of actual
B. 155% of actual
C. 100% of actual
D. 30% of actual

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1 Answers

`a=(v)/(t)`
`x=(m(g-a))/(mg)xx100`

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