Light of wavelength `lambda` is incident on a slit of width d and distance between screen and slit is D. Then width of maxima and width of slit will b

Question

Light of wavelength `lambda` is incident on a slit of width d and distance between screen and slit is D. Then width of maxima and width of slit will b

Light of wavelength `lambda` is incident on a slit of width d and distance between screen and slit is D. Then width of maxima and width of slit will be equal if D is ––
A. `(2lambda^(2))/d`
B. `d^(2)/(2lambda)`
C. `d/lambda`
D. `(2lambda)/d`

Monjur Alahi

6 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
In diffraction fringe width `beta=(lambdaD)/d`
when `d/2=beta" then"d/2=(lambdaD)/drArrD=d^(2)/(2lambda)`

6 views Answered 2023-02-05 15:29