A plane wave of wavelength `6250Å` is incident normally on a slit of width `2xx10^(-2)` cm The width of the principal maximum of diffraction pattern o

Question

A plane wave of wavelength `6250Å` is incident normally on a slit of width `2xx10^(-2)` cm The width of the principal maximum of diffraction pattern o

A plane wave of wavelength `6250Å` is incident normally on a slit of width `2xx10^(-2)` cm The width of the principal maximum of diffraction pattern on a screen at a distance of 50 cm will be
A. `312.5xx10^(-3) cm`
B. `312.5xx10^(-4)cm`
C. `312 cm`
D. `312.5xx10^(-5) cm`

Monjur Alahi

8 views

2025-01-04 04:42

1 Answers

Related Questions

In Fraumhroffer diffraction pattern due to a single slit, the screen is at distance of 100 cm from the slit and slit is illuminated by `lambda=5893Å`.

2 Answers 5 Views

Green light of wavelength 5100 Å from a narrow slit is incident on a double slit . If the overall separation of 10 fringes on a screen 200 cm away is

2 Answers 9 Views

A double - slit apparatus is immersed in a liquid of refractive index `1.33` it has slit separation of 1mm and distance between the plane of slits and

2 Answers 5 Views

A beam of light of wavelength 600 nm from a distance source falls on a single slit 2 mm wide and the resulting diffraction pattern is observed on a sc

2 Answers 6 Views

Light of wavelength 580 nm is incident on a slit having a width of `0.300` nm The viewing screen is 2.00 m from the slit. Find the positions of the fi

2 Answers 8 Views

In a double slit experiment, instead of taking slits of equal widths, one slit is made twice as wide as the other then in the interference pattern.

2 Answers 4 Views

Light of wavelength `lambda` is incident on a slit of width d and distance between screen and slit is D. Then width of maxima and width of slit will b

2 Answers 6 Views

The parallel beams of monochromatic light of wavelength `4.5xx10^(-7)` m passes through a long slit with width `0.2xx10^(-3)` m. The angular divergenc

2 Answers 4 Views

When light of wavelength `lambda` is incident on a metal surface, stopping potential is found to be x. When light of wavelength n`lambda` is incident

2 Answers 8 Views

Two wavelength of sodium light `590 nm` and `596 nm` are used, in turn, to study the diffraction taking placed at a single slit of aperture `2 xx 10^(

2 Answers 4 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - A
According to the question
`lambda=6250 Å=6250xx10^(-10)xx10^(2)cm=6250xx10^(-8)cm`
Width of the slit `a=2xx10^(-2)cm`
The angular width of central maxima `beta=2theta =2lambda/a`
Thus, linear width is
`L=betaxxD=(2lambda)/axxD=(2xx6250xx10^(-8))/(2xx10^(-2))xx50`
`=6250xx10^(-6)xx50=3125xx10^(-4)`
`=312.5xx10^(-3)cm`