In Fraumhroffer diffraction pattern due to a single slit, the screen is at distance of 100 cm from the slit and slit is illuminated by `lambda=5893Å`.

In Fraumhroffer diffraction pattern due to a single slit, the screen is at distance of 100 cm from the slit and slit is illuminated by `lambda=5893Å`. The width of the slit is 0.1 mm. Then separation between central maxima and the first secondary minima
A. `0.5893 cm`
B. `5.893 cm`
C. `0.2946 cm`
D. `2.946 cm `

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

Correct Answer - A
`x=(flambda)/(d)=(100xx5893xx10^(-8))/(0.01)`
0.5893 cm

5 views Answered 2023-02-05 15:29

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