12 g of urea is dissolved in 1 litre os water and 68.4 g of sucrese in also dissolven in 1 lite of water. The lowering in the vapour pressure of first
12 g of urea is dissolved in 1 litre os water and 68.4 g of sucrese in also dissolven in 1 lite of water. The lowering in the vapour pressure of first case is :
A. equal to secound
B. greater than second
C. less than secound
D. double than second.
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Correct Answer - a
Both have same lowering in V.P. as they have same no. of moles.
`"Urea=((12g))/((60g mol^(-1)))=0.2 mol`
`"Sucrose"=(68.4 g)/((342g mol^(-1)))=0.2 mol`
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