Vapour pressure of pure water is 40 mm. if a non-volatile solute is added to it, vapour pressure falls by 4 mm. Hence, molarity of solution is

Question

Vapour pressure of pure water is 40 mm. if a non-volatile solute is added to it, vapour pressure falls by 4 mm. Hence, molarity of solution is

Vapour pressure of pure water is 40 mm. if a non-volatile solute is added to it, vapour pressure falls by 4 mm. Hence, molarity of solution is
A. 6.17m
B. 3.09m
C. 1.54m
D. 0.77m

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
`(Deltap)/(p^(@)) = x_(B)`
`x_(B) = (4)/(40) = 0.1`
Thus, solution contains 0.1 mol of solute in 0.9 mol of water
Mass of water `= 0.9 xx 18 = 16.2 g`
Molarity of solution `= (0.1)/(16.2) xx 1000`
`=(100)/(16.2) = 6.17m`

4 views Answered 2023-02-05 15:29