A solution of sucrose (molar mass =324 g/mol) is prepared by dissolving 68.4 g in 1000 g of water. What is the freezing point and boiling point of the

Question

A solution of sucrose (molar mass =324 g/mol) is prepared by dissolving 68.4 g in 1000 g of water. What is the freezing point and boiling point of the

A solution of sucrose (molar mass =324 g/mol) is prepared by dissolving 68.4 g in 1000 g of water. What is the
freezing point and
boiling point of the solution ? `K_(f)`= water is 1.86 K/m and `K_(b)` =0.52 K/m.

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

Related Questions

Equal volumes of ethylene glycol (molar mass = 62) and water (molar mass = 18) are mixed. The depression in freezing point of water is (given `K_(f)`

2 Answers 5 Views

The freezing point of water is depressed by `0.37^(@)C` in a 0.01 molar NaCI solution. The freezing point of 0.02 molar solution is depressed by

2 Answers 10 Views

A solution of sucrose (molar mass `= 342 g mol^(-1))` has been prepared by dissolving 68.5g of sucrose in 1000g of water. The freezing point of the so

2 Answers 4 Views

A 0.1539 molal aqueus solution of cane sugar `("mol mass" = 342 g mol^(-1))` has a freezing point of 271 K while freezing point ofpure water is 273.15

2 Answers 6 Views

A 10% solution (by mass) pf sicrose in water has freezing point of 269.15 K. Calculate freezing point of 10% glucose in water, if freezing point of pu

2 Answers 4 Views

Calculate the boiling point elevation for a solution prepared by adding 10 g of `CaCI_(2)` to 200 g of water. (`K_(b)` for water = 0.512 K kg mol, Mol

2 Answers 5 Views

A 5% solution (by mass) of cane sugar in water has freezing point of 271 K and freezing point of pure water is 273.15 K. The freezing point of a 5% so

2 Answers 8 Views

A solution of sucrose (molar mass =342 g `mol^(-1)`) has been prepared by dissolving 68.5 g of sucrose in 100 g of water. The freezing point of the so

2 Answers 4 Views

The density of a solution prepared by dissolving 120 g of uree (molar mass = 60 u) in 1000 g of water is 1.15 g/mL The molarity of solution is:

2 Answers 7 Views

A solution of sucrose (molar mass `=342 g mol^(-1)`) has been prepared by dissolving 68.5 g of sucrose in 1000 g of water. The freezing point of the s

2 Answers 4 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - f.p=272.63K, b.p. = 373.1 K
`M_(B)=342" g mol"^(-1), W_(B)=68.4 g, W_(A)=1 kg,`
`K_(f)=1.86Km^(-1), K_(b)=0.52Km^(-1),T_(f)=?, T_(b)=?`
`DeltaT_(f)=(K_(f)xxW_(B))/(M_(B)xxW_(A))" "DeltaT_(f)=(K_(b)xxW_(B))/(M_(B)xxW_(A))`
`=((186" K kg mol"^(-1))xx(68.4 g))/((342" g mol"^(-1))xx(1kg))," "DeltaT_(b)=((0.52" K kg mol"^(-1))xx(68.4g))/((342g)xx(1 kg))`
`=0.372 K," " =0.104 K`
`T_(f)=T_(f)^(@)-DeltaT_(f)=273-0.372," "T_(b)=T_(b)^(@)+DeltaT_(b)=373+0.104`
`=272.628 K" "=373.104 K`