Calculate the boiling point elevation for a solution prepared by adding 10 g of `CaCI_(2)` to 200 g of water. (`K_(b)` for water = 0.512 K kg mol, Mol

Question

Calculate the boiling point elevation for a solution prepared by adding 10 g of `CaCI_(2)` to 200 g of water. (`K_(b)` for water = 0.512 K kg mol, Mol

Calculate the boiling point elevation for a solution prepared by adding 10 g of `CaCI_(2)` to 200 g of water. (`K_(b)` for water = 0.512 K kg mol, Molar mass of `CaCI_(2) = 100 g mol^(-1)`).

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - 0.69 K
`CaCI_(2)" dissociates in aqueous solution"`
`CaCI_(2)(s)overset(("aq"))toCa^(2+)("aq")+2CI^(-)("aq")`
`i=3, W_(B)=10 g, W_(A)=200 g= 0.2, K_(b)=0.512" K kg mol"^(-1)`
`M_(B)=110" g mol"^(-1)`
`DeltaT_(b)=ixxK_(b)m=(ixxK_(b)xxW_(B))/(M_(B)xxW_(A))`
`DeltaT_(b)=((3)xx(0.512" K kg mol"^(-1))xx(10g))/((110" g mol"^(-1))xx(0.2 kg ))=0.69 K`