Molality of an aqueous solution that produce an elevation of boiling point of 1.00 K at 1 atm pressure. `K_(b)` for water is `0.512 K kg mol^(-1)`

Question

Molality of an aqueous solution that produce an elevation of boiling point of 1.00 K at 1 atm pressure. `K_(b)` for water is `0.512 K kg mol^(-1)`

Molality of an aqueous solution that produce an elevation of boiling point of 1.00 K at 1 atm pressure. `K_(b)` for water is `0.512 K kg mol^(-1)`
A. `0.512m`
B. `0.195m`
C. `1.95m`
D. `5.12m`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`Delta T_(b)=K_(b)xxm`
`therefore m=(Delta T_(b))/(K_(b))=(1)/(0.512)=1.953 m`

5 views Answered 2023-02-05 15:29