For the reaction : `2 NH_(3) (g) rarr N_(2) (g) + 3H_(2) (g)`. What is the % of `NH_(3)` converted if the mixture diffuses twice as fast as that `SO_(

Question

For the reaction : `2 NH_(3) (g) rarr N_(2) (g) + 3H_(2) (g)`. What is the % of `NH_(3)` converted if the mixture diffuses twice as fast as that `SO_(

For the reaction : `2 NH_(3) (g) rarr N_(2) (g) + 3H_(2) (g)`. What is the % of `NH_(3)` converted if the mixture diffuses twice as fast as that `SO_(2)` under similar conditions.
A. 3.125
B. 6.25
C. 12.5
D. None of these

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - B
`{:(,2NH_(3) (g),rarr,N_(2) (g),+,3H_(2) (g),),("Initially",1,,,,,),("After",1 - 2x,,x,,3x,):}`
decomposition
`(r_("mix"))/(r_(SO_(2))) = 2 = sqrt((M_(SO_(2)))/(M_("Mix")))`
`M_("mix") = (64)/(4) = 16 = M_("avg")`
`M_(avg) = (1 xx 17)/(1 + 2x) = 16`
`17 = 16 + 32 x`
1 = 32 x
`x = (1)/(32)`
`% NH_(3) = (2x)/(1) xx 100`
`= (1)/(16) xx 100 = 6.25 %`