When the same amount of `Zn` is treated with excess of `H_(2)SO_(4)` and excess of `NaOH` separately, the ratio of the volume of hydrogen evolved is-
When the same amount of `Zn` is treated with excess of `H_(2)SO_(4)` and excess of `NaOH` separately, the ratio of the volume of hydrogen evolved is-
A. `1:1`
B. `1:2`
C. `2:1`
D. `9:4`
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Correct Answer - A
`Zn+H_(2)SO_(4) to ZnSO_(4)+H_(2)`
`Zn+NaOH("excess")to Na_(2)ZnO_(2)+H_(2)`
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