A solid iron rod has a cylindrical shape. Its height is 10 cm and base radius is 7 cm. Then volume of the rod is

A) 1640 cm3

B) 1740 cm3

C) 1440 cm3

D) 1540 cm3

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2 Answers

Correct option is: D) 1540 cm3

Given that height of the cylinder is h = 10 cm

and the base radius is r = 7 cm.

\(\therefore\) Volume of cylindrical rod = \(\pi r^2h\)

\(\frac {22}7\) \(\times\)\(\times\) 7 \(\times\) 10

= 1540 \(cm^3\)

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Correct option is: D) 1540 cm3

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