A solid sphere of radius ‘r’ is melted and cast into the shape of a solid cone of height ‘r’. The radius of the base of the cone is

A) 2r 

B) 3r 

C) 4r 

D) 6r

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2 Answers

Correct option is: A) 2r

Let radius of the base of the cone be R.

\(\because\) Volume of cone = volume of sphere

\(\frac 13 \pi R^2 h\) = \(\frac 43 \pi r^3 h \)

\(R^2 = \frac {4r^3}{h}\) 

\(R^2 = \frac {4r^3}{r}\)\(\because\) h = r)

\(4r^2\) 

= \((2r)^2\) 

\(\therefore\) R = 2r

Hence, the radius of the base of the cone is 2r.

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Correct option is: A) 2r

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