For a reaction `Br_(2)(l)+Cl_(2)(g)to2BrCl` at `300K` the value of `DeltaH=7kcal` and `DeltaS` is `25 cal K^(-1)`. The free energy change is

Question

For a reaction `Br_(2)(l)+Cl_(2)(g)to2BrCl` at `300K` the value of `DeltaH=7kcal` and `DeltaS` is `25 cal K^(-1)`. The free energy change is

For a reaction
`Br_(2)(l)+Cl_(2)(g)to2BrCl` at `300K` the value of `DeltaH=7kcal` and `DeltaS` is `25 cal K^(-1)`. The free energy change is
A. `-500 cal`
B. `7493 cal`
C. `18 kJ`
D. `150 kcal`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
Apply `DeltaG=DeltaH-T DeltaS`
`=7000 cal-300xx25=-500cal`

4 views Answered 2023-02-05 15:29