For a reaction `A+2BtoC+D`, if `DeltaH=-25kcal`, `T=300 K` and `DeltaS=90 cal`, then the reaction is

Question

For a reaction `A+2BtoC+D`, if `DeltaH=-25kcal`, `T=300 K` and `DeltaS=90 cal`, then the reaction is

For a reaction `A+2BtoC+D`, if `DeltaH=-25kcal`, `T=300 K` and `DeltaS=90 cal`, then the reaction is
A. reversible at `300 K`
B. irreversible at `300 K`
C. equilibrium, at `300 K`
D. none of these

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`DeltaG=DeltaH-TDeltaS`
`=-25000 cal mol^(-1)-300 K(90 cal K^(-1)mol^(-1))`
`=-52000 cal mol^(-1)`
Since `DeltaG` is negative, process is spontaneous and hence irreversible thermodynamically.

5 views Answered 2023-02-05 15:29