For reaction `A+2BtoC`. The amount of C formed by starting the reaction with 5 mole of A and 8 mole of B is :

Question

For reaction `A+2BtoC`. The amount of C formed by starting the reaction with 5 mole of A and 8 mole of B is :

For reaction `A+2BtoC`. The amount of C formed by starting the reaction with 5 mole of A and 8 mole of B is :
A. 5 moles
B. 8 moles
C. 16 moles
D. 4 moles

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
`A+2BtoC`
1 mole of A reacts with 10 moles of B
`:.` 5 moles of A will react with 10 moles of B
But we have only 8 moles of B, `:.` B is the limiting reagent
2 moles of B will form 1 mole of C
`:.` 8 moles of B will form C = 4 moles

4 views Answered 2023-02-05 15:29