`Br_(2)` reacts with `O_(2)` in either of the following ways depending upon supply of `O_(2)` `Br_(2) + (1)/(2) O_(2) rarr Br_(2) O` `Br_(2) + (3)/(2)
`Br_(2)` reacts with `O_(2)` in either of the following ways depending upon supply of `O_(2)`
`Br_(2) + (1)/(2) O_(2) rarr Br_(2) O`
`Br_(2) + (3)/(2) O_(2) rarr Br_(2) O_(3)`
If 4 moles of `Br_(2)` and 10 moles of `O_(2)` are taken in a container then calculate the number of moles of reactant left complete reaction.
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Correct Answer - 4
`{:(Br_(2),+,(3)/(2)O_(2),rarr,Br_(2)O_(3),),("Moles",4,,(3)/(2) xx 4,,),(,,,= 6 "moles",,):}`
Moles of reactant `(O_(2))` left = 4 moles
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