The sign of `DeltaG` for the process of melting of ice at `273K` and `1` atm pressure is

Question

The sign of `DeltaG` for the process of melting of ice at `273K` and `1` atm pressure is

The sign of `DeltaG` for the process of melting of ice at `273K` and `1` atm pressure is
A. positive
B. negative
C. neither positive nor negative
D. either positive nor negative

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
Melting of ice is spontaneous above `273 K` at one atm pressure. At `273 K` and `1` atm, there is equilibrium `H_(2)O(s)hArrH_(2)O(l)`
Hence, `DeltaG=0`

4 views Answered 2023-02-05 15:29