`DeltaH_("fus")` is the latent heat of melting and `T_("fus")` is the melting point, then entropy of melting is

Question

`DeltaH_("fus")` is the latent heat of melting and `T_("fus")` is the melting point, then entropy of melting is

`DeltaH_("fus")` is the latent heat of melting and `T_("fus")` is the melting point, then entropy of melting is
A. `DeltaH_("fus")//T_("fus")`
B. `DeltaH_("fus")xxT_("fus")`
C. `T_("fus")//DeltaH_("fus")`
D. `DeltaH_("fus")-T_("fus")`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
`Delta S=(q)/(T)=(DeltaH_("fus"))/(T_("fus"))`

5 views Answered 2023-02-05 15:29