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`NH_(3)(g)+3Cl_(2)toNCl_(3)(g)+3HCl(g),DeltaH_(1)`
`N_(2)(g)+3H_(2)(g)to2NH_(3)(g),DeltaH_(2)`
`H_(2)(g)+Cl_(2)(g)to 2HCl(g),DeltaH_(3)`
The heat of formation of `NCl_(3)`(g) in the terms of
`DeltaH_(1),DeltaH_(2),DeltaH_(3)` is :
A. `DeltaH_(f)=-DeltaH_(1)+(DeltaH_(2))/(2)-(3)/(2)DeltaH_(3)`
B. `DeltaH_(f)=DeltaH_(1)+(DeltaH_(2))/(2)-(3)/(2)DeltaH_(3)`
C. `DeltaH_(f)=DeltaH_(1)-(DeltaH_(2))/(2)-(3)/(2)DeltaH_(3)`
D. None of the above

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1 Answers

Correct Answer - A
The required equation is
`(1)/(2)N_(2)(g)+(3)/(2)Cl_(2)(g)toNCl_(3)(g)`, `DeltaH_(f)=?`
`(i)+(1)/(2)xx(ii)-(3)/(2)xx(iii)`
`DeltaH_(f)=-DeltaH_(1)+(1)/(2)DeltaH_(2)-(3)/(2)DeltaH_(3)`

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