The equilibrium constant for the following reactions are `K_(1)` and `K_(2)`, respectively , `2P(g)+3Cl_(2)(g)hArr2PCl_(3)(g)` `PCl_(3)(g)+Cl_(2)(g)hA
The equilibrium constant for the following reactions are `K_(1)` and `K_(2)`, respectively ,
`2P(g)+3Cl_(2)(g)hArr2PCl_(3)(g)`
`PCl_(3)(g)+Cl_(2)(g)hArrPCl_(5)(g)`
Then the equilibrium constant for the reaction
`2P(g)+5Cl_(2)(g)hArr2PCl_(5)(g)` is -
A. `K_(1)K_(2)`
B. `K_(1)K_(2)^(2)`
C. `K_(1)K_(2)^(2)`
D. `K_(1)^(2)K_(2)`
4 views
1 Answers
Correct Answer - B
`2P(g)+3Cl_(2)(g)hArr2PCl_(3)(g)" "K_(1)`
`2PCl_(3)(g)+2Cl_(2)(g)hArr2PCl_(5)(g)" "K_(2)^(2)`
Net reaction : `2(P)(g)+5Cl_(2)(g)hArr2PCl_(5)(g)" "K=K_(1)K_(2)^(2)`
4 views
Answered