The resistance of the wire in the platinum resistance thermometer at ice point is `5Omega` and at steam point is `5.25Omega`. When the thermometer is
The resistance of the wire in the platinum resistance thermometer at ice point is `5Omega` and at steam point is `5.25Omega`. When the thermometer is inserted in an unknown hot bath its resistance is found to be `5.5Omega`. The temperature of the hot bath is
A. `100^(@)C`
B. `200^(@)C`
C. `300^(@)C`
D. `350^(@)C`
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Correct Answer - B
`"Here", R_(0)=5Omega, R_(100)=5.25Omega,R_(t)=5.5Omega`
`As, R_(1)=R_(0)(1+alphat) therefore R_(100)=R_(0)(1+alpha100)`
`alpha=(R_(1000)-R_(0))/(R_(0)xx100)..(i)`
Equation (i) and (ii), we get
`t=(R_(t)-R(0))/(R_(1000)-R_(0))xx100=(5.5-5)/(5.25-5)xx100=200^(@)C`
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